posted by MELANA .
Posted by MELANA on Thursday, October 18, 2007 at 5:14pm.
An object in equilibrium has three forces exerted on it. A 30 N force acts at 90° from the x-axis and a 44 N force acts at 60° from the x-axis. What are the magnitude and direction of the third force?
NO IDEA WHERE TO START
For Further Reading
IB PHYSICS - bobpursley, Thursday, October 18, 2007 at 6:11pm
add these two forces, then the equilibrant is the equal and opposite force of these two.
add 30j + 44sin60 j + 44 cos60 i
check those components.
IB PHYSICS - MELANA, Thursday, October 18, 2007 at 6:53pm
i got 106.21 would that be the third force?
because i have to find the third force and the degrees(counterclockwise from the +x direction)
but i don't know what angle i am looking for, for the degrees part.