posted by MELANA .
An object in equilibrium has three forces exerted on it. A 30 N force acts at 90° from the x-axis and a 44 N force acts at 60° from the x-axis. What are the magnitude and direction of the third force?
NO IDEA WHERE TO START
add these two forces, then the equilibrant is the equal and opposite force of these two.
add 30j + 44sin60 j + 44 cos60 i
check those components.
i got 106.21 would that be the third force?
because i have to find the third force and the degrees(counterclockwise from the +x direction)
but i don't know what angle i am looking for, for the degrees part.