Ap Calc AB
posted by Student .
Determine (dy/dx) using implicit differentiation.
cos(X^2Y^2) = x
I'm really confused what to do now..i think the next steps are:
d/dx [cos(X^2*Y^2)] = d/dx [x]
= sin(X^2*Y^2)* ((X^2*2Y dy/dx) + (Y^2*2X)) = 1
= 2YX^2 sin(X^2*Y^2) dy/dx + 2XY^2sin(X^2*Y^2) = 1
= 2YX^2 sin(X^2*Y^2) dy/dx = 1 + 2XY^2sin(X^2*Y^2)
= dy/dx = (1 + 2XY^2sin(X^2*Y^2))/ (2YX^2 sin(X^2*Y^2))
Can someone tell me if this is correct?
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