Please check my answers.
Find the x-intercepts (if any) for the graph of the quadratic function.
1.f(x) = (x + 2)2 - 4
I got (0,0) and (-4,0)
Find the y-intercept for the graph of the quadratic function.
5.y + 9 = (x + 3)2
I got (0,0)
Find the domain and range of the quadratic function whose graph is described.
7.The vertex is (1, -15) and the graph opens up.
I got domain: (-infinity, pos.infinity)
range: [-15, pos. infinity)
correct
shanya
Let's check your answers one by one:
1. For the quadratic function f(x) = (x + 2)^2 - 4, you correctly identified the x-intercepts as (0, 0) and (-4, 0). The x-intercepts are the points where the graph of the function intersects the x-axis, and they are found by setting f(x) equal to zero and solving for x.
2. For the quadratic function y + 9 = (x + 3)^2, it seems there may be a mistake in your answer. To find the y-intercept, we need to determine the value of y when x is equal to zero. Plugging in x = 0 into the equation, we have y + 9 = (0 + 3)^2 = 9. Therefore, the y-intercept is (0, 0 + 9) = (0, 9). So the correct answer for the y-intercept is (0, 9), not (0, 0).
3. For the quadratic function with vertex (1, -15) and an upward opening graph, your answer for the domain is correct. The domain of a quadratic function is always all real numbers. However, there seems to be an error in your answer for the range. Since the graph opens upward, the vertex represents the minimum point on the graph of the function. So the range of this quadratic function is all real numbers greater than or equal to the y-coordinate of the vertex, which is -15. Therefore, the correct answer for the range is [-15, +∞), where +∞ represents positive infinity.
Overall, your answers were mostly correct, with a small mistake in the y-intercept for question 2 and an error in the range for question 3. Keep up the good work!