chemistry

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Calculate the mass of sodium hydroxide needed to prepare 500 mL of a 0.10 M solution. I'm pretty sure the answer is 2 grams, but how do I get to that?

  • chemistry -

    mols NaOH = L x M = 0.500 L x 0.10 M = 0.05 mols NaOH.

    Remember mols = grams/molar mass
    Rearrange to obtain
    grams = mols x molar mass = 0.05 mols x (40.0 g/1 mol) = 0.0500 x 40.0 = 2.0 g

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