Algebra

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Can you please help me with the following problems?

Find the coordinates of the vertex for the parabola defined by the given quadratic function.

1.f(x) = (x - 4)2 - 4

Find the axis of symmetry of the parabola defined by the given quadratic function.

3.f(x) = (x + 2)2 + 7

Find the range of the quadratic function.

5.f(x) = 7 - (x + 4)2

  • Algebra -

    for any parabola of the form
    f(x) = a(x-h)^2 + k
    the vertex is (h,k) and the axis of symmetry is x = h

    Make use of that fact for #1 and #3

    The range is the set of y values that the graph covers.
    so in #5 first rewrite it as
    f(x) = -(x+4)^2 - 7

    Wouldn't the vertex be (-4,-7) and since the parabola opens downwards, what do you thing would be the y values covered by the graph?

  • Algebra -

    Please check my answers.

    Find the coordinates of the vertex for the parabola defined by the given quadratic function.

    1.f(x) = (x - 4)2 - 4
    -I got (4,-4)

    Find the axis of symmetry of the parabola defined by the given quadratic function.

    3.f(x) = (x + 2)2 + 7
    -I got: x=-2

    Find the range of the quadratic function.

    5.f(x) = 7 - (x + 4)2
    I got: (-inifinity,7]

  • Algebra -

    find the coordinates of the vertex for the parabola defined by the given quadratic function f(x)=(x+7)^2-6

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