Algebra
posted by Soly .
Can you please help me with the following problems?
Find the coordinates of the vertex for the parabola defined by the given quadratic function.
1.f(x) = (x  4)2  4
Find the axis of symmetry of the parabola defined by the given quadratic function.
3.f(x) = (x + 2)2 + 7
Find the range of the quadratic function.
5.f(x) = 7  (x + 4)2

for any parabola of the form
f(x) = a(xh)^2 + k
the vertex is (h,k) and the axis of symmetry is x = h
Make use of that fact for #1 and #3
The range is the set of y values that the graph covers.
so in #5 first rewrite it as
f(x) = (x+4)^2  7
Wouldn't the vertex be (4,7) and since the parabola opens downwards, what do you thing would be the y values covered by the graph? 
Please check my answers.
Find the coordinates of the vertex for the parabola defined by the given quadratic function.
1.f(x) = (x  4)2  4
I got (4,4)
Find the axis of symmetry of the parabola defined by the given quadratic function.
3.f(x) = (x + 2)2 + 7
I got: x=2
Find the range of the quadratic function.
5.f(x) = 7  (x + 4)2
I got: (inifinity,7] 
find the coordinates of the vertex for the parabola defined by the given quadratic function f(x)=(x+7)^26
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