Prealgebra
posted by Jillian .
How do you do these probelms?
1. 7p+11=31
2. 127y=2
3. 2z4z=4
4. 105h+2=32
5. 7k8k=1
6. 10d=19
7. 9x+54x=20
8. 34t+11=2
9. 5b+66b+2=19

1. Subtract 11 from both sides, to get rid of the 11. Then solve for p.
7p+11=31
11 11
7p=42
Then divide by 7 to get rid of the 7.
p=6
Does that help? 
Ms. Sue's response is more clear than mine. My computer didn't put some numbers in the right spot.

7p+11=31
7p = 31  11
7p = 42
p = 6
Follow this pattern for solving the rest of the problems.
If you post your answers, we'll be glad to check them for you.
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