physics please help
posted by Anonymous .
A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 11.0 m/s when the hand is 1.50 m above the ground.
How long is the ball in the air before it hits the ground? (The student moves her hand out of the way.)
initial velocity is 15 and final velocity is zero. acceleration is 9.8 right.
how does height fit into this equation. isn't that necessary too.
can u please help me. i keep getting .738s as my answer
height (y) vs time is given by
y = 1.50 + 11 t - 4.9 t^2.
Solve for the time (t) when y = 0. You will have to solve a quadratic equation. Take the positive one of the two answers.
You don't use the velocity vs. time equation in this problem.