A basketball player, standing near the basket to grab a rebound, jumps 73.6 cm vertically. How much time does the player spend in the top 15.4 cm of his jump?
I never know which formula to use for these problems! Any help will be greatly appreciated.
If you dropped an object, how long does it take for it to travel 15.4cm? Double this time to account for both the rising and falling motion.
To find the time, would I have to use the formula "x = vt + 1/2at^2?"
Yes, solve for t for x=15.4cm. For starting at the top, the players initial velocity is 0. So the first term drops out. The calculated time is one half of the total time. Remember that for constant acceleration the time going up is the same as the time going down.
I found the time. Now I just have to double it, and that will be the time he spent in the top 15.4 cm?
Ok n/m, I got the answer.
However, now it asks for the time in the bottom 15.4 cm. Do I have to use my time from the first problem to figure it out?