1.A race car has a mass of 707 kg. It starts from rest and travels 42.0 m in 3.0 s. The car is uniformly accelerated during the entire time. What net force is exerted on it?
Is is possible for you to post some thinking here?
Do I use F=ma so then m=707 and a=42/3 which is 14. So m=707 and a=14 and I multiply and it's 9898 N?
3299.33
To find the net force exerted on the race car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
First, let's find the acceleration of the race car. We can use the equation of motion:
distance = initial velocity * time + (1/2) * acceleration * time^2
Since the race car starts from rest (initial velocity = 0), the equation simplifies to:
distance = (1/2) * acceleration * time^2
Rearranging the equation, we can solve for acceleration:
acceleration = (2 * distance) / (time^2)
Plugging in the given values:
acceleration = (2 * 42.0 m) / (3.0 s)^2
acceleration = (2 * 42.0 m) / 9.0 s^2
acceleration = 84.0 m / 9.0 s^2
acceleration = 9.33 m/s^2
Now that we know the acceleration, we can find the net force using Newton's second law:
net force = mass * acceleration
net force = 707 kg * 9.33 m/s^2
net force = 6594.31 N
Therefore, the net force exerted on the race car is 6594.31 N.