I need to divide this but I am a little confused. I hope this makes sense I tried to make sure I have the parenthesis in all the right spots
[(x^2-49y^2)/(6x^2+42y)] / (x^2 - 7xy)
[(x^2-49y^2)/(6x^2+42y)]*[1/(x^2 - 7xy)]
{[(x+7y)(x-7y)]/6(x^2+7y)]}*[1/ x(x-7y)]
{[(x-7y)]/6(x^2+7y)]}*[1 / x]
(x+7y) / [6x(x^2+7y)]
According to your original line you are correct, but...
are you sure that the second bracket wasn't (6x^2+42xy) ?
Then I would have worked out better and the answer would have been 1/(6x^2)
nope I am positive it is the way I have it written. This problem has caused me more grief because I thought there should have been a "x" in it also. Thanks for looking at it for me.
To divide the expression [(x^2-49y^2)/(6x^2+42y)] by (x^2 - 7xy), you can follow these steps:
Expression before division:
[(x^2-49y^2)/(6x^2+42y)] / (x^2 - 7xy)
Next, multiplying the numerator by the reciprocal of the denominator:
[(x^2-49y^2)/(6x^2+42y)] * [1/(x^2 - 7xy)]
Now, let's factorize the numerator and denominator where possible:
[(x+7y)(x-7y)] / [6(x^2+7y)] * [1/(x(x-7y))]
Further simplifying the expression, observe that (x-7y) appears in both the numerator and the denominator, so it cancels out:
[(x+7y)] / [6(x^2+7y)] * [1 / x]
Finally, we have:
(x+7y) / [6x(x^2+7y)]
Thus, the division of the given expression is (x+7y) / [6x(x^2+7y)].