# algebra

posted by .

I need to divide this but I am a little confused. I hope this makes sense I tried to make sure I have the parenthesis in all the right spots

[(x^2-49y^2)/(6x^2+42y)] / (x^2 - 7xy)

[(x^2-49y^2)/(6x^2+42y)]*[1/(x^2 - 7xy)]

{[(x+7y)(x-7y)]/6(x^2+7y)]}*[1/ x(x-7y)]

{[(x-7y)]/6(x^2+7y)]}*[1 / x]

(x+7y) / [6x(x^2+7y)]

• algebra -

According to your original line you are correct, but...

are you sure that the second bracket wasn't (6x^2+42xy) ?

Then I would have worked out better and the answer would have been 1/(6x^2)

• algebra -

nope I am positive it is the way I have it written. This problem has caused me more grief because I thought there should have been a "x" in it also. Thanks for looking at it for me.

## Similar Questions

2. ### math/algebra

20 Divide: x^2 -49y^2/6x^2+42y divided by (x^2-7xy) = factor the first term. Multiply the first term by the inverse of the second.Combine terms. I will be happy to critique your work. (x-3)(x+5)/2(2x^2) * 2x-10 /x^2 - 25 = x-3/2x^2 …
3. ### intermidate algebra

Just not good at this, factor complete, or state that the polynomial is prime. 9y^4+42y^3+49y^2 (9+y)(9-y)+42(y+3)(y-3)^2+49(y+2(y-2) I can not seem to get it right. so help me please
4. ### algebra

64y^3-125 9y^4+42y^3+49y^2 I need help I cannot get the right answer. factor complete, or state that the polynomial is prime.
5. ### DIVIDING BINOMIALS

find the quotient: (-49y^4+42y^3)/7y
6. ### algebra

36x^2 - 49y^2 divided by 6x + 7y meaning 36x^2 - 49y^2 is on top and 6x + 7y is on bottom. Please help, my teacher nor course book covers when there are different variables
7. ### algebra

Essay. Show all work. Find the following quotient: 36x^2-49y^2 ----------- 6x+7y