Algebra 2
posted by Audrey .
1.) Write a system of equations that has NO solution.
2.) If you wanted to eliminate the y variables in the system of equations below, what would you multiply the first and second equations by?( Do not solve the equation) 2x3y=8
7x4y=11

Try
x+t=14
2x+2y=28
2. If you multiply #1 by 4 the coefficient of y will be 12. Multiply #2 by 3 will give the coefficient of y as 12. \Subtracting then would eliminte y.
Check my thinking. 
2.)
Multiply the first equation by 4 and the second equation by 3.
4(2x  3y = 8), so 8x  12y = 32
3(7x  4y = 11), so 21x + 12y = 33
So, the first equation has 12y and the second equation has 12y, so the y variables cancel out. 
Try
x+t=14
2x+2y=28
I made a typo. first equation should be x+y=14 y and not t.
Note that Adams' response eliminates y by addition in problem #2. My response eliminates y by subtraction. Either is correct.