HOW MANY DIFFERENT ARRANGEMENTS ARE THERE OF THE LETTERS IN TESTERS?
This is a permutation.
n! (n factorial) = n(n-1)(n-2)...1
What is your n?
http://en.wikipedia.org/wiki/Permutation
I hope this helps. Thanks for asking.
My solution assumed that each letter — even if repeated — was considered different. Thus T1 is considered different from T2 and so on.
I hope this helps a little more. Thanks for asking.
To find the number of different arrangements of the letters in the word "TESTERS," we can use the concept of permutations.
The word "TESTERS" has a total of 7 letters. To determine the number of arrangements, we need to calculate the number of permutations for these 7 letters.
Step 1: Find the total number of arrangements by using the formula for permutations:
n! / (n-r)!
where n is the total number of letters and r is the number of letters being arranged.
In this case, n = 7 (total number of letters) and r = 7 (all the letters are being arranged).
So, the formula becomes:
7! / (7-7)!
Step 2: Simplify the expression:
7! / 0! = 7!
Step 3: Evaluate the factorial:
7! = 7 x 6 x 5 x 4 x 3 x 2 x 1 = 5040
Therefore, there are 5040 different arrangements of the letters in the word "TESTERS."