help me calculate this - my 6th grade nephew has this question for homework and I'm at a loss.
The combined age of 2 people is 91. Person A is two times as old as Person B was when Person A was as old as Person B is now.
My stab at it...
A+B=91 (Combined age)
A=2B
B=91-A (Age of Person B now)
Substituting:
A=2(91-A) = 60.66 or 60 2/3
60.66+B=91
B=30.33 (or 30 1/3)
Sure! Let's break down the problem step by step.
We are given two people, let's call them person A and person B. We don't know their actual ages, but we know that their combined age is 91. So we can set up an equation using their ages:
A + B = 91
Now, let's move on to the second part of the problem. It says that person A is two times as old as person B was when person A was as old as person B is now. This might seem a bit confusing, but let's break it down.
Let's assume person A is currently X years old, and person B is currently Y years old. The problem states that there was a point in time when person A was as old as person B is now. So at that time, person A's age must have been Y.
Now, let's look at person B's age at that time. The problem states that person B's age at that time was X. However, we're also told that person A is now two times as old as person B was at that time. So we can write an equation using this information:
A = 2 * (B - X)
Now we have two equations:
A + B = 91
A = 2 * (B - X)
We can now solve this system of equations to find the ages of person A and person B.