How many kilograms of chlorine are in 30kg of each of the following chlorofluorocarbons (CFC's)?
CF2Cl2 -in kg's;
CFCl3 -in kg's;
C2F3Cl3 -in kg's?
ok...so I took 30,000g * 1/120.913g/mol = 248.1122g. Then I went: 248.1122g * 70.906g/mol & got: 17592g = 18kg. Does this look correct? should I carry it through to the rest?
I will be happy to critique your thinking.
I obtained 17.592 kg chlorine which rounds to 18 kg to two significant figures. Note: You need not convert 30 kg to grams and convert back.
30 kg x (2 mols Cl/1 mol CF2Cl2) = 30 x (70.905/120.913) = 17.592 kg chlorine, then round to 18 kg. The others are done the same way.
thank you.
Why did the CFC go to the circus? It wanted to feel more chloro-fun!
Now, let's calculate the amount of chlorine in each compound:
1. CF2Cl2:
Well, each CF2Cl2 molecule has 2 chlorine atoms. So, we can multiply by 2 to get the amount of chlorine in 30 kg of CF2Cl2. That means there are 60 kg of chlorine in 30 kg of CF2Cl2. Careful, chlorine can make quite a splash!
2. CFCl3:
In this case, each CFCl3 molecule has 3 chlorine atoms. So, let's multiply by 3. That means there are 90 kg of chlorine in 30 kg of CFCl3. That's a whopping chlorine party!
3. C2F3Cl3:
This compound contains 3 chlorine atoms. However, we are given the quantity in kilograms, so we don't need to do any calculations here. The amount of chlorine in 30 kg of C2F3Cl3 is simply 30 kg.
Remember, though, while it's good to know these numbers, it's even better to remember to protect our ozone layer from these substances! Let's keep things clean and green!
To determine the number of kilograms of chlorine in each compound, we need to know the molecular formula of each chlorofluorocarbon (CFC).
The molecular formula of CF2Cl2 (Dichlorodifluoromethane) consists of two chlorine atoms and two fluorine atoms bonded to a single carbon atom. Since the atomic mass of chlorine is approximately 35.45 g/mol, we can calculate the molar mass of CF2Cl2 as follows:
Molar mass of CF2Cl2 = (2 * atomic mass of Cl) + (2 * atomic mass of F) + atomic mass of C
= (2 * 35.45 g/mol) + (2 * 18.99 g/mol) + 12.01 g/mol
= 70.9 g/mol + 37.98 g/mol + 12.01 g/mol
= 120.89 g/mol
Since 1 kg is equal to 1000 g, we can now calculate the number of kilograms of chlorine in 30 kg of CF2Cl2:
Number of kg of CF2Cl2 = (30 kg / molar mass of CF2Cl2) * (2 * atomic mass of Cl / molar mass of CF2Cl2)
= (30 kg / 120.89 g/mol) * (2 * 35.45 g/mol / 120.89 g/mol)
≈ 6.2418 kg
Therefore, there are approximately 6.2418 kilograms of chlorine in 30 kg of CF2Cl2.
Similarly, to find the number of kilograms of chlorine in CFCl3 (Trichlorofluoromethane) and C2F3Cl3 (Trichlorotrifluoroethane), we can follow the same steps using their respective molecular formulas and atomic masses of chlorine.