im in a cal class but were reviewing algebra stuff now. and i have 1 more questions.
it says.
express the given quantity as a single loragithms
2ln4-ln2
so is it 2ln(2)
please tell me if im getting the right answers and if im not then please show me how to do it. thank you for reading.
2ln4 - ln2 = ln[(4^2)/2] = ln 8
2 (ln4 - ln2)= 2 ln 2
Did you omit parentheses?
lgnheymjw gbfnk nxztarwd hkndqozbf niuwbxck hunbka vros
if i bought a 16 ounce bottle of water for 1.09, how many gallons will that be?
(2x+3)exponet2over3=3
To express the given quantity, 2ln4 - ln2, as a single logarithm, you can use the logarithmic rule known as the "difference rule."
The difference rule states that when you subtract two logarithms with the same base, you can rewrite it as the logarithm of the division of the arguments.
So, let's apply the difference rule to the expression 2ln4 - ln2:
2ln4 - ln2 = ln(4^2) - ln(2)
Now, simplify further:
= ln(16) - ln(2)
Finally, you can use another logarithmic rule called the "quotient rule" that states when you divide two logarithms with the same base, you can rewrite it as the logarithm of the division of their arguments.
Therefore, the expression simplifies to:
= ln(16/2)
= ln(8)
Hence, the expression 2ln4 - ln2 is equivalent to ln(8).