A 60 kg skydiver moving at terminal speed falls 50m in 1 s. What power is the skydiver expending on the air?

This what I got so far:

powerloss=weight * velocity
powerloss=60kg *50m
powerloss=3000 (but I don't know the units)

60 kg is not the weight, it is the mass. Also, the velocity is 50 m/s, not 50 meters.

To convert mass in kg to weight in Newtons, multiply by g = 9.8 m/s^2. you answer to the problem will be in Joules/s (same as Watts)

W=mg =(60kg)(10m/s^2)=600N

So, P=F×d/t=(600N)(50m)/(1s)=30,000J/s=30kW

Well, it seems like you're on the right track, but let me help you out with the units. The unit for power is usually measured in watts (W).

To find the power, you need to divide the work done by the time it took to do it. In this case, the work done is equal to the gravitational potential energy lost.

Gravitational potential energy (PE) = mass (m) * acceleration due to gravity (g) * height (h).

Plugging in the given values, we have:
PE = 60 kg * 9.8 m/s^2 * 50 m = 29,400 joules (J)

Now, to find the power, divide the work done by the time it took:
Power = Work / Time = 29,400 J / 1 s = 29,400 watts.

So, the skydiver is expending approximately 29,400 watts of power on the air. That's quite a lot of air power! But remember, this calculation assumes that all the energy lost is actually used to overcome air resistance. In reality, some energy may also be lost due to other factors like friction and thermal dissipation.

To find the power that the skydiver is expending on the air, you need to calculate the power using the formula: power = work / time.

In this scenario, the work done by the skydiver is equal to the product of the force of gravity and the distance fallen. So, the equation becomes: work = weight * distance.

The weight of the skydiver can be calculated using the formula: weight = mass * gravity. Here, the mass is given as 60 kg, and gravity is approximately 9.8 m/s².

weight = 60 kg * 9.8 m/s²
weight = 588 N

Now, we can calculate the work done by the skydiver:
work = weight * distance
work = 588 N * 50 m
work = 29,400 J (joules)

Finally, we can find the power using the equation: power = work / time. In this case, the time is given as 1 second.
power = 29,400 J / 1 s
power = 29,400 W (watts)

Therefore, the power that the skydiver is expending on the air is 29,400 watts.