I cant figure out this problem.
A pool is rectangular in shape, with a half-circle at one end. The length is 80 feet; the width is 30 feet; depth is 4ft the half-circle is appended to one of the thirty-foot sides, so that end is curved. Find the surface area of the pool.
The rectangular portion can be found by mutiplying the length by the width. The side for the half-circle is the diameter. Using this, you can find the area of half of the circle. Add the two areas together.
If you are looking for the surface area, the depth is irrelevant information.
I hope this helps. Thanks for asking.
To find the surface area of the pool, we need to calculate the areas of individual components and then add them up.
1. Let's start by calculating the area of the rectangular portion of the pool. The rectangular portion has dimensions of length 80 feet and width 30 feet. So the area of the rectangular portion is 80 ft × 30 ft = 2400 square feet.
2. Now let's calculate the area of the half-circle portion. Since the half-circle is appended to one of the 30-foot sides, the half-circle's radius is equal to the width of the rectangular portion, which is 30 feet. The formula to calculate the area of a half-circle is A = (1/2)πr^2, where r is the radius. Plugging in the values, we get A = (1/2) × π × 30 ft × 30 ft = (1/2) × π × 900 square feet.
3. Finally, we add the areas of the rectangular and half-circle portions to get the total surface area of the pool. Total surface area = Area of rectangular portion + Area of half-circle portion = 2400 square feet + (1/2) × π × 900 square feet = 2400 + 450π square feet.
Therefore, the surface area of the pool is 2400 + 450π square feet.