Sodium Chloride NaCl can be made by the reaction of sodium with chlorine.
Balanced equation:
2Na(s)+Cl2(g)=2NaCl(s)
Calculate the maximum mass of sodium chloride which could be obtained from 92g of soium?
moles=mass/Mr
92/23= 4 moles
4x (NaCl)
4x(23+35.5)
234 g
To calculate the maximum mass of sodium chloride (NaCl) that can be obtained from 92g of sodium (Na), we need to use stoichiometry. The balanced equation shows that 2 moles of sodium react with 1 mole of chlorine gas (Cl2) to produce 2 moles of sodium chloride.
1. Convert the mass of sodium to moles:
Molar mass of sodium (Na) = 22.99 g/mol
Number of moles of sodium = mass of sodium / molar mass of sodium
Number of moles of sodium = 92 g / 22.99 g/mol
2. Use the mole ratio to determine the number of moles of sodium chloride:
From the balanced equation, the ratio of sodium (Na) to sodium chloride (NaCl) is 2:2 (or 1:1).
Number of moles of sodium chloride = number of moles of sodium
3. Convert the moles of sodium chloride to mass:
Molar mass of sodium chloride (NaCl) = 58.44 g/mol
Mass of sodium chloride = number of moles of sodium chloride × molar mass of sodium chloride
Using the given values, we can now calculate the maximum mass of sodium chloride that can be obtained from 92g of sodium.
Number of moles of sodium = 92 g / 22.99 g/mol = 4.004 mol
Number of moles of sodium chloride = 4.004 mol
Mass of sodium chloride = 4.004 mol × 58.44 g/mol = 233.8 g
Therefore, the maximum mass of sodium chloride that can be obtained from 92g of sodium is 233.8g.