Physics

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A boat moving at 15 km/h relative to water is crossing a river 1.5 km wide. The river flows at 5.0 km/h
a) if the boat heads directly for the opposite shore, how long will the trip take?
b)Where will the boat arrive on the opposite shore?
c)If the boat is to reach a point directly across from the starting point , in which direction should the boat head?
d)How long will the crossing take in case c)?

  • Physics -

    It will take 1.5/15 hr to get across

    IT does downstream 5*1.5/15 km

    For the c), draw the triangle. On side is 5km/hr, the hypotenuse is 15km/hr. Solve for the side going straight across, that is the velocity across. For the angle, SinTheta=5/15

  • Physics -

    i didn't get the answer of bob very well. can he help me more widely.
    the question is


    Q)A boat moving at 15 km/h relative to water is crossing a river 1.5 km wide. The river flows at 5.0 km/h
    a) if the boat heads directly for the opposite shore, how long will the trip take?
    b)Where will the boat arrive on the opposite shore?
    c)If the boat is to reach a point directly across from the starting point , in which direction should the boat head?
    d)How long will the crossing take in case c)?

  • Physics -

    use this, Vx = dx * t
    then use that t and find
    Vy = dy * t
    x and y are x dimension n y dimension
    uhh..
    i'll just do it,
    Vx= 15 km/hr
    dx = 1.5 km
    dy = 5 km/hr

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