what is the equation passing through
a)y=5.04x=50
y=6.13 x=100
y=8.24 x=150
y=10.3 x=200
y=10.45 x=250
b)y=7.63 x=50
y=11.3x=100
y=12.52x=150
y=14.45x=200
y=14.48 x=250
(x+3)(x+6)find the prodduct by inspection
x y 1.determine whether each
-2 5 relation is a function.
8 6 if the relation ia a
3 12 function, state the
5 6 domain and range.
To determine the equation passing through the given points, we can use the slope-intercept form of a linear equation, which is:
y = mx + b
where m represents the slope of the line and b represents the y-intercept.
For example, let's calculate the equation passing through the points in part (a):
Point 1: (x = 50, y = 5.04)
Point 2: (x = 100, y = 6.13)
Point 3: (x = 150, y = 8.24)
Point 4: (x = 200, y = 10.3)
Point 5: (x = 250, y = 10.45)
To find the slope, we need to calculate the change in y divided by the change in x for any two points. We can use the formula:
slope (m) = (change in y) / (change in x)
Applying this formula for the first two points:
slope = (6.13 - 5.04) / (100 - 50) = 1.09 / 50 = 0.0218
Now, let's pick any of the given points to find the y-intercept (b). We will use Point 1 (50, 5.04):
y = mx + b
5.04 = 0.0218(50) + b
5.04 = 1.09 + b
b = 5.04 - 1.09
b = 3.95
Therefore, the equation passing through the given points in part (a) is:
y = 0.0218x + 3.95
You can follow the same procedure to find the equation passing through the points in part (b). Simply substitute the given values into the slope-intercept form equation (y = mx + b) and calculate the slope and y-intercept accordingly.