A 6 kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 1 m/s2, find the force exerted by the rope on the bucket of water.

Rope Force - M g = M a

M =6 kg
g = 9.8 m/s^2
a = 1 m/s^2

Solve for the force

To find the force exerted by the rope on the bucket of water, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a), represented by the equation F = ma.

Given:
Mass of the bucket (m) = 6 kg
Acceleration (a) = 1 m/s^2

Substituting the values into the equation, we get:
F = 6 kg × 1 m/s^2

Calculating the force:
F = 6 kg × 1 m/s^2
F = 6 N

Therefore, the force exerted by the rope on the bucket of water is 6 Newtons.

To find the force exerted by the rope on the bucket of water, we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.

In this case, the mass of the bucket of water is given as 6 kg, and the upward acceleration is 1 m/s². Therefore, the force exerted by the rope on the bucket can be calculated as:

Force = Mass × Acceleration

Force = 6 kg × 1 m/s²

Force = 6 N

So, the force exerted by the rope on the bucket of water is 6 Newtons.