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One integer is 4 more than a second integer. Three times the first integer when added to two times the second integer is less than 23. Determine the largest possible values of the two integers.

  • Math -

    9 divided by 66

  • Math -

    Let x = one integer and x + 4 = the second.

    3x + 2(x+4) < 23

    Solve for x and x+4.

    I hope this helps. Thanks for asking.

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