One to one functions
posted by Jessica .
I still need help with finding the inverese of one to functions.
Find the inverese of the one to one function.
16. f(x)= 4/(5x1)
This is what I've done so far.
y=4/(5x1)
x= 4/(5y1)
(5y1)x= 4(5y1)
Then I am not too sure what to do next.

The last line is wrong:
(5y1)x= 4
5yx= 4+x
y= (x+4)/5x 
y=(x+4)/5x, doesnt match up with what I am suppose to get.
I am suppose to get:
a. f^1(x)=4/(5y) +1/5, b. f^1(x)=4/(5x) +1/(5), c. f^1(x)= 1/(5) 4/(5x), or d. f^1(x)=5x1/(4) 
y=(x+4)/5x= 1/5 +4/5x
x=1/5+4/5y
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