how many mL of a .25 M HCL would be required to neutralize completely 30mL of a .2 M Ca(OH)2
NormalityAcid*volumeacid=Normalitybase*Vb
The normalality of the acid here is .25N
the normality of the base here is .40N
solve for volume acid.
The normalality of the acid here is .25N
the normality of the base here is .40N
solve for volume acid.