A number cube is marked with 1,2,3,4,5, and 6 on its faces. Suppose you roll the number cube one time. Find the probability of each event.
#1. P(4) #2. P(4,5, or 6)
#3. P(3 or 5)
Could someone let me know if these are correct, THANK YOU!
#1. 1:6 1/6 1 to 6
#2. 1:2 1/2 1 to 2
#3. 1:3 1/3 1 to 3
To find the probability of an event, you need to divide the number of favorable outcomes by the total number of possible outcomes.
In this case,
1. P(4): The number cube has one face marked with a 4. So, there is 1 favorable outcome (getting a 4) out of 6 possible outcomes (rolling any number between 1 and 6). Therefore, the probability is 1/6.
2. P(4, 5, or 6): The number cube has three faces marked with 4, 5, and 6. So, there are 3 favorable outcomes (getting a 4, 5, or 6) out of 6 possible outcomes. Therefore, the probability is 3/6 or simplified as 1/2.
3. P(3 or 5): The number cube has two faces marked with 3 and 5. So, there are 2 favorable outcomes (getting a 3 or 5) out of 6 possible outcomes. Therefore, the probability is 2/6 or simplified as 1/3.
So, your answers are correct.
Your calculations for the probabilities are correct. Here are the probabilities for each event:
#1. P(4) = 1/6
#2. P(4, 5, or 6) = 3/6 = 1/2
#3. P(3 or 5) = 2/6 = 1/3
So, your answers are correct.