A jumbo jet taxiing down the runway receives word that it must return to the gate to pick up an important passenger who was late to his connecting flight. The jet is traveling at 45.0 m/s when the pilot resieves the messae. What is the acceleration of the plane if it takes the pilot 5.00 s to bring the plane to halt?
i need the work too not just the answer, i need to know how it is done.. the steps and stuff,
To find the acceleration of the plane, we can use the equation:
acceleration (a) = (final velocity (vf) - initial velocity (vi)) / time taken (t)
Given:
Initial velocity (vi) = 45.0 m/s
Final velocity (vf) = 0 m/s (since the plane comes to a halt)
Time taken (t) = 5.00 s
Substituting the values into the equation:
a = (0 - 45.0) / 5.00
Now let's subtract the initial velocity (45.0 m/s) from the final velocity (0 m/s):
a = (-45.0) / 5.00
This simplifies to:
a = -9.00 m/s²
Therefore, the acceleration of the plane is -9.00 m/s².
Note: The negative sign indicates that the plane is decelerating or slowing down.
A jet taxiing down the runway receives word that it must return to the gate. The jet is traveling 44.1 m/s when the pilot receives the message. What is the acceleration of the plane if it takes the pilot 6.18 s to bring the plane to a halt?
oko
Vfinal=vinitial + a*t
you know all except a, solve for that. Notice it is negative.