what kind of question is this?

Rowing 5 times the speed of current, jacob's team can travel 24 km downstream and at the sametime 16 km upstream. What is jacob's team rate and the rate of the water?

This is a word problem involving rates of rowing and the speed of water current. To solve it, we need to use a system of equations.

Let's assume the rate of Jacob's team is represented by "R" and the rate of the water current is represented by "C".

Given that the team can row 5 times the speed of the current, we can write the equation for rowing downstream as follows:

(R + C) = 5C

Similarly, for rowing upstream, we can write the equation:

(R - C) = C

We can now solve this system of equations to find the values of R and C.

First, let's simplify the equation (R + C) = 5C by moving the "C" terms to one side:

R = 4C

Next, substitute this value of R in the equation (R - C) = C:

4C - C = C
3C = C

Simplifying further, we find:

3C = C
2C = 0
C = 0

Since C = 0, it means that the rate of the water current is 0 km/h.

Substituting this value into the equation R = 4C, we find:

R = 4(0)
R = 0

Therefore, Jacob's team rate is 0 km/h, and the rate of the water is also 0 km/h.