The mass of a single silver atom is 1.79E-22 grams. How many silver atoms would there be in 143 milligrams of silver?
divide 143mg by 1.79E-22 grams
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143mg/1.79E-22g
To find the number of silver atoms in 143 milligrams of silver, we need to use the concept of molar mass and Avogadro's number.
1. Convert the mass of silver from milligrams to grams:
143 milligrams = 143/1000 grams = 0.143 grams
2. Calculate the number of moles of silver:
Molar mass of silver (Ag) = 107.87 g/mol (approximately)
Number of moles = mass/molar mass = 0.143 grams / 107.87 g/mol ≈ 0.001326 moles
3. Use Avogadro's number to find the number of silver atoms:
Avogadro's number (NA) = 6.022 × 10^23 atoms/mol
Number of atoms = number of moles × Avogadro's number = 0.001326 moles × 6.022 × 10^23 atoms/mol ≈ 7.98 × 10^20 atoms
Therefore, there would be approximately 7.98 × 10^20 silver atoms in 143 milligrams of silver.