posted by Jenna .
A dog searching for a bone walks 4.31 m south, then runs 8.93 m at an angle 22.0 north of east, and finally walks 10.0 m west. Find the magnitude of the dog's resultant displacement vector.
Add the three vectors.
The +y (north) component of the sum is
X = -4.31 +8.93 sin 22
The +x (east) component of the sum is
Y = 8.93 cos 22 - 10.0
The magnitude of the displacement vector is sqrt(X^2 + Y^2)
The direction (counterclockwise from east) is arctan Y/X
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