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physics

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A dog searching for a bone walks 4.31 m south, then runs 8.93 m at an angle 22.0 north of east, and finally walks 10.0 m west. Find the magnitude of the dog's resultant displacement vector.

  • physics -

    Add the three vectors.
    The +y (north) component of the sum is
    X = -4.31 +8.93 sin 22

    The +x (east) component of the sum is
    Y = 8.93 cos 22 - 10.0

    The magnitude of the displacement vector is sqrt(X^2 + Y^2)

    The direction (counterclockwise from east) is arctan Y/X

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