solve each following system by substitution 4x-12y=5 -x+3y=-1
I think something is wrong with your problem...
I assume the two equations are as follows:
4x-12y=5 and
-x+3y=-1
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To solve by substitution, take either equation, I'll take #2, and solve for either x or y. I'll solve for x, so
-x + 3Y = -1
-x = -1-3y
multiply through by -1 to give
x=1+3y. Now that value of x goes into x in equation #1.
#1 is
4x-12y=5
substitute the value of x you have from the work bove.
4(1+3y)-12y=5 and solve for y.
This is the way to eliminate one of the variables. Post your work if you get stuck.
Thanks
To solve the system of equations by substitution, follow these steps:
Step 1: Solve one of the equations for one of the variables.
Let's solve the second equation for x:
-x + 3y = -1
-x = -1 - 3y
x = 1 + 3y
Step 2: Substitute the value of x from Step 1 into the other equation.
Substitute x = 1 + 3y into the first equation:
4x - 12y = 5
4(1 + 3y) - 12y = 5
4 + 12y - 12y = 5
4 = 5
Step 3: Determine if there is a valid solution.
Since the equation 4 = 5 is not true, the system of equations does not have a solution. The lines represented by these equations are parallel and will never intersect.
Therefore, the system of equations is inconsistent and has no solutions.