WHEN THE NUMBER 29 IS INCREASED BY THE SUM OF ITS DIGITS, THE RESULT IS 40 (IE 29 +2+9=40). WHAT NUMBER WHEN INCREASED BY THE SUM OF ITS DIGITS RESULTS IN 73?

59

CAN U TELL HOW THIS WAS WORKED OUT?

5 + 9 = 14

73 - 14 = 59

To find the number that, when increased by the sum of its digits, results in 73, we can follow a similar approach as the given example (29 + 2 + 9 = 40).

Let's assume the unknown number as "N" and its digits as "D1" and "D2".

We know that N increased by the sum of its digits (D1 + D2) equals 73.

So, the equation we need to solve is:
N + D1 + D2 = 73

Since we don't have specific information about the number N, we'll try different possibilities until we find one that satisfies the equation.

Let's start with a guess:
Assume N = 70
This means D1 + D2 = 73 - 70 = 3
If we try different combinations of D1 and D2, we find that there are no two digits that sum up to 3. So, 70 is not the correct number.

Next, let's try another guess:
Assume N = 60
This means D1 + D2 = 73 - 60 = 13
By trying different combinations, we find that D1 = 1 and D2 = 12 work, as 1 + 12 equals 13.
So, the number is 60.

Therefore, when we increase the number 60 by the sum of its digits (1 + 2), we get 60 + 1 + 2 = 63, which is not the desired result (73).

Since 60 did not give us the correct answer, we need to continue exploring other possibilities by guessing different numbers for N until we find the correct one that satisfies the equation N + D1 + D2 = 73.