AT THE ZOO, THERE ARE OSTRICHES AND DEER IN THE SAME ENCLOSURE. JARROD COUNTED 60 HEADS AND 160 LEGS. HOW MANY ANIMALS OF EACH TYPE WERE IN THE ENCLOSURE?

To solve this problem, we can set up a system of equations using the information given. Let's say the number of ostriches is represented by "o" and the number of deer is represented by "d."

From the problem, we know that the total number of heads is 60 and the total number of legs is 160. Since each animal has one head and either two or four legs, we can set up the following equations:

1. o + d = 60 (equation 1, representing the total number of heads)
2. 2o + 4d = 160 (equation 2, representing the total number of legs)

Now, we can solve this system of equations to find the values of "o" and "d."

First, let's simplify equation 2 by dividing both sides by 2 to make it easier to work with:

2o + 4d = 160 becomes
o + 2d = 80 (equation 3)

Next, we can use equation 1 and equation 3 to solve for either "o" or "d."

We'll solve for "d" in terms of "o" using equation 1:

o + d = 60
d = 60 - o (equation 4)

Now, substitute equation 4 into equation 3:

o + 2d = 80
o + 2(60 - o) = 80
o + 120 - 2o = 80
120 - 80 = o - 2o
40 = -o
o = -40

We have a negative value for "o," which doesn't make sense in this context. Therefore, we made a mistake somewhere or the information provided is inconsistent.

Please double-check the problem, and let me know if there are any additional details or corrections.