# Algebra 3-4

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What is the number feared by Pythagoreans since it lies halfway between the only two integers that can be both the perimeter and the area of the same rectangle?

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sin theta = squre roote of 3 over 4 what is the number feared by pythagoreans, since it lies halfway between the only two intergers that can be both the perimeter and the area of the same rectangle Here is a hint. 16 is one of the …
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what is the number feared by the pythagoreans I googled "number feared by the Pythagoreans" and checked the 3rd entry. This is what I found on that web site. Find the number feared by Pythagoreans, since it lies halfway between the …

If you have a rectangle with 24 square units 3 lines down 8 across how can you have a 4 unit rectangle with a perimeter of 8 around the outside also 6 units with a perimeter of 10 in a seprate problem A square of 4, perimeter of 8. …
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one of the two numbers that can be both the perimeter and the area of the same rectangle I am assuming that you are seeking the two rectangles that have the area equal to the perimeter. A 4 x 4 square has a perimeter and area of 16. …
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i need help finding the base. this is the equation i got after work it out halfway. 42/h+h+sqroot(42/h)^2+h^2=20 ft how can i find B & H. How should i go about. Thanks. Isnt the sqrt of (42/h)^2 just 42/h ?
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The number of feared by Pythagoreans, since it lies halfway between the only two integers that can be both the perimeter and the area of the same rectange
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The number feared by Pythagoreans, since it lies halfway between the only two integers that can be both the perimeter and the area of the same rectangle?
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the number feared by phythagoreans since it ties halfway between the only two integers that can be both the perimeter and the area fo the same triangle
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The perimeter of rectangle P is 12 feet. The perimeter of rectangle Q is 18 feet. Both rectangles have the same area.Find the area and dimensoin of each rectangle.
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please check this. 1. What is a reasonable distance between two cities?

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