if x-3y=8 and y=2x+1, then x= ???

Substitute 2x+1 into equation 1 for y and solvee for x.

huh??

x-3(2x+1)=?

since y=2x+1

x-3y=8 and y=2x+1, then x= ???

x-3(2x+1)=??

you have to solve it by multiplying the 3 over and then just adding the x's and the #'s without the x's

Nobody's going to give you all the answers.

im not asking for da answer I juss don't know how to do it.... im confused....

so i multiply the 3&1 ( right??)
then i add the #'s with x's... 1x + 2x which is 3x^2.... see i don't know wat im doing.... becasue the multiply choices are single digits or fractions....

well

x-3(2x+1)=

multiply the -3 and the 2x+1
then add

thank u..... & sorry if i was rude... i was just confused...

if x-3y=8 and y=2x+1, then x=

To find the value of x, we'll substitute the value of y from the second equation into the first equation.

Given:
x - 3y = 8 ...(Equation 1)
y = 2x + 1 ...(Equation 2)

Substituting y = 2x + 1 in Equation 1:
x - 3(2x + 1) = 8

Expanding the brackets:
x - 6x - 3 = 8

Combining like terms:
-5x - 3 = 8

Now, let's isolate x by moving the constant term to the other side:
-5x = 8 + 3
-5x = 11

Finally, divide both sides of the equation by -5 to solve for x:
x = 11/(-5)
x = -11/5 or x = -2.2

Therefore, the value of x is -11/5 or -2.2.