Algebra1
posted by unknown .
i think i have to simplify.... but the question just says:
(2y3)^2
a.4y^2+9
b.4y^26y+9
c.4y^212y+9
d.4y^2+12y+9
i got A but i wanna make sure....

Algebra1 
Mr. Kim
yes... A. is the correct answer.

Algebra1 
DrBob222
Just expand the binomial.
You know how to do it?
First term is (2y)^2 = 4y^2.
Second term is twice the product inside the parentheses which is 2y*3 = 6y and twice that is 12y.
The third term is the last number squared which is 3^{2} or +9. Do you see any answers that fit that? I do. If you will learn the method I showed you, you can do these things in your head. 
Algebra1 
DrBob222
A point of clarification: A is not the correct answer.
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