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how would you solve this;
Write an equation for the hyperbola with vertices (-10,1) and (6,1) and foci (-12,1)and (8,1)

The centre is the midpoint between the vertices, which is ((-10+6)/2,(1+1)/2) or (-2,1)

so the equation looks like
(x+2)^2/a^2 - (y-1)^2/b^2 = 1

a is the distance from the centre to the vertex, so a = 8
c is the distance between the centre and the focal point, so c = 10
In a hyperbola a^2 + b^2 = c^2
so 64 + b^2 = 100
b^2 = 36

your equation would be

(x+2)^2/64 - (y-1)^2/36 = 1

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