I need some help with some problems as well as need some checked. Could you please help me? Thanks!

1. How do you graph y=1/x
2. How do I the x and y intecepts using a graph?

Solve and check the linear equation.

9. (-4x-2)+7=-3(x+3) I got 14

10. -2[7x-7-6(x+1)]=2x+5 I got 21/4

Solve the equation.

13. (x+7)/4=2-(x-1)/6 I am not too sure how to do this one.

Find all the values of x satisfying the given conditions.

16. y1= (x+6)/3, y2=(x+8)/6, and y1=y2 This one I don't understand.

First write the value(s) that make the denominator(s) zero. Then solve the equation.

19. (x-8)/2x +5= (x+6)/x This one I also don't understand.

Determine whether the equation is an identity, a conditional equation, or inconsistent equation.

24. -2(x+7)+52=4x-6(x+3) I got Inconsistent

25. (3x+2)/4 +2= -7x/2 I got inconsistent

I need some help with some problems as well as need some checked. Could you please help me? Thanks!

1. How do you graph y=1/x make a table of values, x vs y. Plot the values
2. How do I the x and y intecepts using a graph? The question makes no sense as typed

Solve and check the linear equation.

9. (-4x-2)+7=-3(x+3) I got 14
correct
10. -2[7x-7-6(x+1)]=2x+5 I got 21/4
correct
Solve the equation.

13. (x+7)/4=2-(x-1)/6 I am not too sure how to do this one.
multiply both sides by 12, then reduce the equation
Find all the values of x satisfying the given conditions.

16. y1= (x+6)/3, y2=(x+8)/6, and y1=y2 This one I don't understand. If y1=12, then (x-6)/3=(x+8)/6 . multiply both sides of the equation by six, then gather terms.

Sorry, I meant to ask how do I find the x and y intercepts using a graph.

Hi, I need some help with some inequalitites. Thanks!!

Use graphs to find the set.

1.(-9,0) intersection [-4,] I got [-4,0)

2. (-9,0) U [-4,10] I got (-9,10]

Solve the linear inequality. Other than (empty set, use interval notation to express the solution set and graph the solution set on a number line.

4. 21x -21>3(6x-2) I got x<5, graph would be <------)5

5. 5(4x+7)-4x<4(8+4x)-6 I got 0>9, but I don't know how the graph would be.

6. 6(x+4)> or equal to 5(x-3)+x I got 0 > greater than or equal to -39, but don't know how the graph would be.

Solve the compound inequality. Other than empty set, use interval notation to express the solution set and graph the solution set on a number line.

10. -24 < or equal to -5x+1 < -9 I am not too sure how to solve this.

14. 3 < or equal to (8/5x)-5<11 one this one am I suppose to multiply each side by 5 to undo the fraction.

Solve the absolute value inequality. Other than empty set, use interval notation to express the solution set and graph the solution set on a number line.

20. |x+9| -4 < or equal to I got [-5 -13] and the graph would be <----)-13 -5---->

21. |10y+30/3| < 10 This one I don't understand what to.

Hi, I need some help with some inequalitites. Thanks!!

Use graphs to find the set.

1.(-9,0) intersection [-4,] I got [-4,0)

2. (-9,0) U [-4,10] I got (-9,10]

Solve the linear inequality. Other than (empty set, use interval notation to express the solution set and graph the solution set on a number line.

4. 21x -21>3(6x-2) I got x<5, graph would be <------)5

5. 5(4x+7)-4x<4(8+4x)-6 I got 0>9, but I don't know how the graph would be.

6. 6(x+4)> or equal to 5(x-3)+x I got 0 > greater than or equal to -39, but don't know how the graph would be.

Solve the compound inequality. Other than empty set, use interval notation to express the solution set and graph the solution set on a number line.

10. -24 < or equal to -5x+1 < -9 I am not too sure how to solve this.

14. 3 < or equal to (8/5x)-5<11 one this one am I suppose to multiply each side by 5 to undo the fraction.

Solve the absolute value inequality. Other than empty set, use interval notation to express the solution set and graph the solution set on a number line.

20. |x+9| -4 < or equal to I got [-5 -13] and the graph would be <----)-13 -5---->

21. |10y+30/3| < 10 This one I don't understand what to.

Post under a new post Christie

Sure, I can help you with your problems. Let's start with your questions about graphing, solving equations, and solving inequalities.

1. To graph the equation y = 1/x, you can start by creating a table of values. Choose different values for x, and then calculate the corresponding values of y by substituting x into the equation. For example, if you choose x = -2, then y = 1/(-2) = -1/2. Repeat this process for several values of x, and then plot the points on a graph. Connect the points to create the graph of the equation.

2. To find the x-intercepts and y-intercepts of a graph, you need to identify the points where the graph intersects the x-axis and the y-axis, respectively. For the x-intercepts, set y = 0 and solve for x. For example, in the equation y = 1/x, the x-intercept occurs when y = 0. Solve 0 = 1/x to find that x = 0. So, the x-intercept is (0, 0). For the y-intercept, set x = 0 and solve for y. In this case, when x = 0, y is undefined because you can't divide by zero. Therefore, there is no y-intercept for the equation y = 1/x.

Now let's move on to solving equations and inequalities.

9. (-4x - 2) + 7 = -3(x + 3)
To solve this equation, start by simplifying both sides.

-4x - 2 + 7 = -3x - 9
-4x + 5 = -3x - 9
Next, move all the x terms to one side of the equation.

-4x + 3x = -9 - 5
-x = -14
Finally, divide both sides of the equation by -1 to solve for x.

x = 14

You got it correct! Well done.

10. -2[7x - 7 - 6(x + 1)] = 2x + 5
Let's simplify the equation step by step.

-2[7x - 7 - 6x - 6] = 2x + 5
-2[7x - 6x - 7 - 6] = 2x + 5
-2[x - 13] = 2x + 5
-2x + 26 = 2x + 5
Next, move all the x terms to one side of the equation.

-2x - 2x = 5 - 26
-4x = -21
Finally, divide both sides of the equation by -4 to solve for x.

x = 21/4

Great job! You are correct.

13. (x + 7)/4 = 2 - (x - 1)/6
To solve this equation, we can start by eliminating the fractions.

Multiply both sides of the equation by the least common denominator (LCD), which is 12.

12 * (x + 7)/4 = 12 * (2 - (x - 1)/6)

After multiplying both sides, simplify the equation.

3(x + 7) = 24 - 2(x - 1)

Now, distribute and simplify to get rid of the parentheses.

3x + 21 = 24 - 2x + 2

Combine like terms on both sides.

3x + 2x = 24 + 2 - 21

5x = 5

Divide both sides of the equation by 5 to solve for x.

x = 1

Well done! You found the correct solution.

I'll continue with the remaining problems in the next response.