algebra
posted by Marissa .
1)Write the expression 9n^6+7n^36 in quadratic form,if possible
A.9(n^3)^3+7n^36
B.9(n^2)^3+7(n^2)6
C.9(n^3)^2+7(n^3)6
D.not possible
I'm thinking C on this one but im not sure
2)solve b^4+2b^224=0
A.2,square root of 6,square root of 6,2
B.square root of 6,2,2i,i square root of 6
C.2,2,isquare root of 6
D.2i,2i, square root of 6,square root of 6
3)If f(x)= x^2+1 and g(x)= x2,find f[g(x)]
A.x^24x+5
B.x^21
C.x^23
D.x^32x^2+x2
my answer is B
4)Find the inverse of f(x)= 2x7
=f1(x)= x+7/2
5)Determine which pair of functions are inverses:
A.f(x)= 3x1;g(x)= 1/3x1
B.f(x)= 2x5;g(x)= x+5/2
C.f(x)= 2x+2;g(x)= 2x2
D.f(x)= 3x8;g(x)= 1/3x+8
my answer is D or B
2.) C
3.)A
f[g(x)] = (x2)^2 + 1
= x^2 4x +5
4.)correct
5.) B
Follow the same procedure you did for number 4
1. C is right
2. b^4 + 2b^2  24 = 0
b^4 + 2b^2 = 24
b^4 + 2b^2 + 1 = 24 + 1
(b^2 + 1)^2 = 25
b^2 + 1 = ± 5
b^2 = 4 or b^2 = 6
b= ±2 or b= ±i√6
3. I got A
f[g(x)]
= f(x2)
= (x2)^2 + 1
= x^2  4x + 4 + 1
= x^2  4x + 5
4. ok if you include brackets as in (x+7)/2
5 ok if you include brackets as in (x+5)/2 and (1/3)(x+8)
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