compound inequality
posted by Telli .
olve. State the solution set using interval notation and graph it
1/3x > 2 and 1/4x > 2
First should I solve for x. How would you handle this problem?
yes, solve for x in each..
x>6; x>8
so if the second condition is met, that is x is g reater than eight, the first is not applicable.
first solve each of the inequalities
here is the first:
1/3x > 2
1 > 6x
6x<1
x<1/6
in the same way from the second, x<1/8
Also it should be obvious that x cannot be zero or a negative, since 1/(a negative) is not greater than 2
so we have x<1/6 AND x<1/8
so the only values that would work are
0 < x < 1/8
See how important it is to use proper notation?
if you meant (1/3)x > 2 and (1/4)x > 2
then bobpursley's solution is correct
if you meant 1/(3x) > 2 and 1/(4x) > 2
then my solution is correct.
5N+34NGRAETER THEN 53N
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