How many different 5- member committees can be formed from 9 students?
A.24 B.126 C.15,120 D.362880
9!/(5!*4!)
1*2*3*4*5*6*7*8*9/[(1*2*3*4*5)(1*2*3*4)]
= 6*7*8*9/(1*2*3*4)
=126
To find the number of different 5-member committees that can be formed from 9 students, we can use the formula for combinations:
C(n, r) = n! / (r!(n-r)!)
In this case, we want to find C(9, 5). Plugging in the values:
C(9, 5) = 9! / (5!(9-5)!)
= 9! / (5! * 4!)
= (9 * 8 * 7 * 6 * 5 * 4!) / (5! * 4!)
= 9 * 8 * 7 * 6 / (1 * 2 * 3 * 4)
= 9 * 8 * 7
Simplifying further:
9 * 8 * 7 = 504
Therefore, the number of different 5-member committees that can be formed from 9 students is 504.
However, none of the given answer choices match this value. The correct answer is not provided among the options listed.