# Math

posted by
**Tashanna**
.

How many different 5- member committees can be formed from 9 students?

A.24 B.126 C.15,120 D.362880

9!/(5!*4!)

1*2*3*4*5*6*7*8*9/[(1*2*3*4*5)(1*2*3*4)]

= 6*7*8*9/(1*2*3*4)

=126

posted by
**Tashanna**
.

How many different 5- member committees can be formed from 9 students?

A.24 B.126 C.15,120 D.362880

9!/(5!*4!)

1*2*3*4*5*6*7*8*9/[(1*2*3*4*5)(1*2*3*4)]

= 6*7*8*9/(1*2*3*4)

=126