# math 117

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A garden area is 30 ft long and 20 ft wide. A path of uniform width
is set around the edge. If the remaining garden area is 400 ft2, what is the width of
the path?

I did the following:
Let x = distance between the inner rectangle and the outer boundry; i.e., x is the width of the border. Then
length is 20-x-x and the width is 20-x-x so (30-x-x)(20-x-x)=400
Solve for x.
Post your work if you get stuck.

• math 117 -

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