write a balanced equation for the combustion of benzene.
All hydrocarbons, like benzene are, are the same. Add O2. C goes to CO2 and H goes to H2O.
C6H6 + O2 ==> CO2 + H2O
I will let you balance it. Let me know if you have a problem with it.
would it be...
C6H6 + 14O2 --> 6C02 + 4H2O
To balance the combustion equation for benzene, we need to ensure that the number of atoms on both sides of the equation is equal. Here's the correct balanced equation for the combustion of benzene:
C6H6 + 15O2 → 6CO2 + 3H2O
To balance the equation, we first count the number of atoms on each side:
Carbon (C):
Left side: 6 carbons (C6H6), Right side: 6 carbons (6CO2)
Balanced.
Hydrogen (H):
Left side: 6 hydrogens (C6H6), Right side: 6 hydrogens (3H2O)
Balanced.
Oxygen (O):
Left side: 15 oxygens (15O2), Right side: 12 oxygens (6CO2 + 3H2O)
To balance the oxygens, we need to add a coefficient in front of the O2 on the left side. The lowest whole number that balances the oxygens is 15.
C6H6 + 15O2 → 6CO2 + 3H2O
Now the equation is balanced with respect to carbon, hydrogen, and oxygen, with 6 carbon atoms, 6 hydrogen atoms, and 30 oxygen atoms on both sides of the equation.