nuclear chem
posted by kenny .
i need help solving this. Can you guys show me how it's done.
Radium226 decays by alpha emission to radon222, a noble gas.What volume of pure Radon 222 at 23oC and 785mmHg could be obtained from 543.0 mg of radium bromide,RaBr2 in a period of 20.2 years.The halflife of radium226 is 1602 years.
k = 0.693/t_{1/2}
plug in the half life of Ra226 and calculate k. THEN, convert 543.0 mg RaBr2 to mg Ra. I will call that value No. Use No in the following formula to calculate N (t is the time of 20.2 years.)
ln(No/N) = kt
From N, which is mg Ra remaining, calculate how much has decayed, convert the amount decayed into mass of Rn222 and use PV = nRT to calculate the volume Rn at the conditions specified. Check my thinking.
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