physics

posted by .

Determine the fraction of the energy radiated by the sun in the visible region of the spectrum (350 nm to 700 nm). (Assume the sun's surface temperature is 5800 K.)

any help is always appreciated

thanks

Solve by integrating the 5800 K blackbody function from 350 to 700 nm, and dividing by the total output per unit area, sigma T^4.

We will be glad to critique your work.

Note: The blackbody function is usually quoted as spectral radiance (output per area per steradian per wavelngth). You must multiply that by pi to get output per area per wavelength.

what is the blackbody function?

It is what you need to use to do this problem. Is there a textbook assiciated with your course?

You can read aboutit at http://en.wikipedia.org/wiki/Planck's_law_of_black_body_radiation



am i supposed to integrate the function with respect to the wavelength?

yes. The answer should be about 0.6

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. physics

    The difference between energy radiated from the sun and energy radiated from the Earth has to do with ____________________. A) Neither of these.B) Both of these.C) radiation frequencies.D) the amounts of radiant energy.
  2. physics

    The difference between energy radiated from the sun and energy radiated from the Earth has to do with ____________________. A) Neither of these.B) Both of these.C) radiation frequencies.D) the amounts of radiant energy.
  3. physics

    The sun is 1.5 1011 m from the earth. (a) Over what surface area is solar radiation spread at this distance?
  4. physics

    the energy received by the earth from the sun is 1400w/m2. Assuming that the sun is a black body radiator and the ratio of the radius of the earth's orbit to the sun's radius is 216. Calculate the surface temperature of the sun. Stefan …
  5. astronomy

    The red supergiant Betelgeuse has a surface temperature of 3600 K. a) Using the fact that the Sun's surface temperature is about 5800 K and that its continuous spectrum peaks at a wavelength of 500 nm, find the peak wavelength of Betelgeuse's …
  6. astronomy

    The red supergiant Betelgeuse has a surface temperature of 3600 K. a) Using the fact that the Sun's surface temperature is about 5800 K and that its continuous spectrum peaks at a wavelength of 500 nm, find the peak wavelength of Betelgeuse's …
  7. metreology

    Wien’s radiation law says that the wavelength of most intense radiation (λmax) emitted by a blackbody is inversely proportional to the absolute temperature (T) of the object. The surface of the Sun radiates as a blackbodyat …
  8. Physics

    The temperature of the Sun’s surface (the so-called photosphere) is about 5500 C. Assume that the Sun’s surface is pretty close to a perfect black-body emitter. (a) At what wavelength does the peak intensity of Sun’s radiation …
  9. physics

    the rate at which radiant energy from the sun reaches the earth's upper atmosphere is about 1.50kW/m2. the distance from the earth to the sun is 1.50*10^11m, and the radius of the sun is 6.96 * 10^8m. if the sun radiates as an ideal …
  10. astronomy

    The red supergiant Betelgeuse has a surface temperature of 3600 K. a) Using the fact that the Sun's surface temperature is about 5800 K and that its continuous spectrum peaks at a wavelength of 500 nm, find the peak wavelength of Betelgeuse's …

More Similar Questions