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Determine the fraction of the energy radiated by the sun in the visible region of the spectrum (350 nm to 700 nm). (Assume the sun's surface temperature is 5800 K.)

any help is always appreciated


Solve by integrating the 5800 K blackbody function from 350 to 700 nm, and dividing by the total output per unit area, sigma T^4.

We will be glad to critique your work.

Note: The blackbody function is usually quoted as spectral radiance (output per area per steradian per wavelngth). You must multiply that by pi to get output per area per wavelength.

what is the blackbody function?

It is what you need to use to do this problem. Is there a textbook assiciated with your course?

You can read aboutit at's_law_of_black_body_radiation

am i supposed to integrate the function with respect to the wavelength?

yes. The answer should be about 0.6

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