Calculus  series
posted by COFFEE .
I'm getting this answer wrong, can someone please help show me what i'm missing?? thank you :)
Infinity of the summation n=0: [(1)^n pi^(2n)] / [6^(2n) (2n)!]
this is my work:
[(1^0) pi^(2*0)] / [6^(2*0) (2*0)!] + [(1^1) pi^(2*1)] / [6^(2*1) (2*1)!] + [(1^2) pi^(2*2)] / [6^(2*2) (2*2)!] + [(1^3) pi^(2*3)] / [6^(2*3) (2*3)!]
1 + 0.13707783 + 0.00313172 + 0.0000286 + 0.00000014
sum of the series = 1.14023829
You got the signs wrong. The answer is 1/2 sqrt[3]
thank you!!!
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