algebra2
posted by anonymous .
evaluate h(2/3) if h(x) = [[x2]]
(2/3)2 = 2.666666667
is this the right correct?
If those are absolute value signs surrounding the x2 on the right, then the answer is +2.666..= 8/3
why is it a positive 8/3 instead of a negative because you subtracted 2 from negative 2/3
As I said earlier, it looks like you might have absolute value signs ( )around the
8/3. That would make the final answer positive. If those are just brackets [ ] (which would serve no mathematical purpose here) then the answer would be 8/3.
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