evaluate h(-2/3) if h(x) = [[x-2]]

(-2/3)-2 = -2.666666667

is this the right correct?

If those are absolute value signs surrounding the x-2 on the right, then the answer is +2.666..= 8/3

why is it a positive 8/3 instead of a negative because you subtracted 2 from negative 2/3

As I said earlier, it looks like you might have absolute value signs (| |)around the
-8/3. That would make the final answer positive. If those are just brackets [ ] (which would serve no mathematical purpose here) then the answer would be -8/3.

To evaluate h(-2/3) using the given function h(x) = |x - 2|, we first substitute -2/3 for x in the function:

h(-2/3) = |-2/3 - 2|

Next, we simplify the expression inside the absolute value brackets by performing the subtraction:

h(-2/3) = |-2/3 - 6/3|

Combining the like terms, we get:

h(-2/3) = |-8/3|

At this point, we need to determine whether the value inside the absolute value brackets is positive or negative. If it is positive, then the absolute value will not affect the value and the result will be the same. On the other hand, if the value inside the absolute value brackets is negative, then taking the absolute value will convert it to its positive equivalent.

In this case, -8/3 is indeed negative. Taking its absolute value means we convert it to its positive equivalent:

h(-2/3) = 8/3

So, the correct answer is 8/3, not -8/3.