can somenone please check my answer and if i'm doing it right....
The sum of a number and 17 more than twice the same number is 101.
N+17(2)=101 N=67?
N + (2N +17)= 101
3N = 84
Take it from there
THANK YOU! =)
To check your answer, we need to substitute the value of N back into the original equation and see if it holds true. Let's solve it step by step:
Original equation: N + (2N + 17) = 101
Substituting N = 67 into the equation:
67 + (2 * 67 + 17) = 101
67 + (134 + 17) = 101
67 + 151 = 101
218 = 101
This statement is not true, which means your answer, N = 67, is not correct.
So, let's solve the equation correctly:
N + (2N + 17) = 101
We can simplify it by combining like terms:
3N + 17 = 101
Now, subtract 17 from both sides of the equation to isolate 3N:
3N = 101 - 17
3N = 84
Finally, divide both sides of the equation by 3 to solve for N:
N = 84 / 3
N = 28
Therefore, the correct value of N is 28.