Writing this equation
posted by Katty .
how do I write the equation of a line perpendicular to the line 6x – 3y=10 and containing the point (6, 2).
The line you are given can have its equation rewritten im y = mx + b as:
y = 2x  10/3
That tells you that is slope is m = 2. A line that is perpendicular to that must have a slope of 1/2, because the product of slopes of perpendicular lines must be m = 1. (Trust me on that one, or check your textbook.)
A new perpendicular line going through a point (x*,y*) will have the equation
y  y* = m (x  x*)
y  2 = (1/2)(x (6))
y  2 = x/2  3
y = (x/2) 1
(y  )/(
Ignore the last line of my last answer. It's some leftover garbage I neglected to delete
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