Can someone show me how to solve this? Someone tried to explain it to me-I didn't get it.A line contains the points (3, -4) and (5, 2). Another line graphed in the same coordinate plane contains the points (0, 5) and (-2, -1). Based on the slopes of these lines are they parallel, perpendicular or neither?
The slope of any line from point 1 to point 2 is (y2-y1)/(x2-x1). Therefore the slopes of the two lines you are talkng about are
(2 -(-4))/(5-3) = 6/2 = 3
and
(-1 -(5)/(-2-0)= -6/-2 = 3
Thelines are therefore parallel because they have the same slope.
To determine if the lines are parallel, perpendicular, or neither, we need to compare their slopes. The slope of a line is given by the formula:
slope = (change in y)/(change in x)
Let's calculate the slopes of the two lines:
1. Line 1: (3, -4) and (5, 2)
slope = (2 - (-4))/(5 - 3)
slope = (2 + 4)/(5 - 3)
slope = 6/2
slope = 3
2. Line 2: (0, 5) and (-2, -1)
slope = (-1 - 5)/(-2 - 0)
slope = -6/-2
slope = 3
From the calculations, we can see that both lines have a slope of 3. Therefore, they are parallel because parallel lines have the same slope.
To determine if the two lines are parallel, perpendicular, or neither, we need to compare their slopes. The slope of a line can be found using the formula (y2 - y1)/(x2 - x1), where (x1, y1) and (x2, y2) are two points on the line.
Let's find the slope of the first line using the given points (3, -4) and (5, 2):
slope = (2 - (-4))/(5 - 3) = (2 + 4)/(5 - 3) = 6/2 = 3
Now, let's find the slope of the second line using the given points (0, 5) and (-2, -1):
slope = (-1 - 5)/(-2 - 0) = (-1 - 5)/(-2) = -6/-2 = 3
After calculating the slopes of both lines, we can see that they have the same slope of 3. Therefore, the lines are parallel because parallel lines have equal slopes.
In conclusion, based on the slopes of the two lines, they are parallel.